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1 point by rincewind 5721 days ago | link | parent

If I write this into the foo-package-file:

   (let list '(this is a test case)
       (all is-a-foo (map make-a-foo list)))
would list be read as <foo>list or <arc>list? Should the expression

   (sym "make-a-foo")
evaluate to <foo>make-a-foo?


2 points by almkglor 5721 days ago | link

> If I write this into the foo-package-file: ....

Assuming you mean in the same file with the example foo package:

  (<arc>let <arc>list (<axiom>quote (<arc>this <arc>is <foo>a <foo>test <arc>case))
    (<arc>all <foo>is-a-foo (<arc>map <foo>make-a-foo <arc>list)))
> Should the expression ....

No, it evaluates to the unpackaged symbol 'make-a-foo.

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