arc> (= al '((k1 v1) (k2 v2))) ((k1 v1) (k2 v2)) arc> (alref al 'k2) v2 arc> (listtab al) #hash((k1 . v1) (k2 . v2))
arc> (obj 1 2 3 4 5 6 7 8 9 0 a 2 b 3 r 4) ;; Is 0 a key or a value? #hash((r . 4) (1 . 2) (b . 3) (3 . 4) (a . 2) (5 . 6) (7 . 8) (9 . 0)) arc> (listtab '((1 2) (3 4) (5 6) (7 8) (9 0) (a 2) (b 3) (r 4))) ;; a val. #hash((r . 4) (1 . 2) (b . 3) (3 . 4) (a . 2) (5 . 6) (7 . 8) (9 . 0))