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Suggestion: how to improve arc.
1 point by ylando 5252 days ago | 19 comments
First use & instead of dot in functions before rest. for example (def func (a b . rest) ...) => (def func (a b & rest) ... ) It will make macro writing much easier.

Second add a function that is ignored by the compiler. It can be use when we write macros for metadata manipulation. For example when we want to declare a name to have a property: we can write:

  (mac declare (name prop) (= metadata*.name prop) 
                   '(ignore))


5 points by shader 5252 days ago | link

Not sure exactly what you're going for with the "function ignored by the compiler" Maybe a few more examples would be more helpful?

In general, when you have things that you want to improve about arc, I would recommend one of two things:

1) If your change is merely syntactical, or is trying to get arc to use a different style of programming (oop, etc.) try doing things the arc way for a while, and see if you can't learn to appreciate it the way it is. It's quite possible that after a while you'll learn to prefer the traditional lisp/arc method.

2) If you're writing on the forum about changes that you'd like to see made to arc, try implementing them and submitting them first. This will allow the community to experiment with your ideas and give better criticism, as well as give you a greater understanding of why things are the way they are, and how hard it might be to change them.

This is an "open source" community. That means you have just as much opportunity to implement your desired feature as everyone else, but a better understanding of it and a lot more interest in getting it done. If you don't feel like implementing your feature, odds are no one else will either.

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2 points by fallintothis 5252 days ago | link

Maybe a few more examples would be more helpful?

Seconded. In this example, what's the problem with metadata-manipulating macros? Seems you should expand them into something that sets the metadata.

  (mac declare (name prop)
    `(= (metadata* ',name) ,prop))
What does ignoring accomplish, here or elsewhere? If you don't want a return value, just return nil -- though, almost always, having one won't hurt.

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1 point by ylando 5252 days ago | link

Suppose we want to declare a name inside a function We must use it outside of the function definition For example:

  (declare int_value int
  (def myfunc (...) ...
     (let int_value 3 ... )))

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2 points by fallintothis 5252 days ago | link

I still don't follow. A) Why do we need "ignores" here? B) Why would we need to use the declaration outside of the definition? Expressions can be sequenced. I.e., wouldn't you do something like this?

  (def f (x y)
    (let i 3
      (declare integer i)      ; this is evaluated and sets metadata...
      (something-with x y i))) ; ...but THIS is the value that gets returned
Similarly,

  (def foo (bar)
    (let baz 10
      (prn "hello") ; evaluates and returns the string "hello"
      (+ bar baz))) ; evaluates and returns bar + 10

  arc> (foo 5) ; prints hello and returns 15
  hello
  15

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1 point by ylando 5252 days ago | link

In the example above you waste run time on declaring i as integer.

Suppose we want to declare the value for a region of code; like a let statement. We can do it in the following way:

  (mac declare (name prop . body) 
     (let oldprop (metadata* name)
       (= (metadata* name) prop)
       `(do (= temporary* (do ,@body)) (undeclare ,name ,oldprop))))

  (mac undeclare (name oldprop) 
    (= (metadata* obj) oldprop)
    'temporary*)
If we put it in a function body, we still waste time.

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1 point by zck 5252 days ago | link

I think fallintothis declared i as an integer because ey was trying to translate your code, which declares int_value as an integer.

So the 'temporary call serves to tell the 'do in 'declare not to return the value from 'undeclare, but instead to return the value from the (= temporary* (do ,@body)) line?

This seems a lot more complicated than simply saving the value in a 'let or using do1.

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2 points by fallintothis 5252 days ago | link

This seems a lot more complicated than simply saving the value in a 'let or using do1.

There's also a typo:

  (mac undeclare (name oldprop)
    (= (metadata* name) oldprop)    ; was (= (metadata* obj) oldprop)
    'temporary*)
Even fixing that, the metadata-setting happens at macroexpansion time, so you get

  arc> (def f (x) (declare x integer (prn "metadata*: " metadata*) (+ x 5)))
  #<procedure: f>
  arc> metadata*
  #hash()
  arc> (f 5)
  metadata*: #hash()
  10
  arc> metadata*
  #hash()
At no point before, after, or in the body is the metadata actually in the hash table. It was just there for a brief pause between the macroexpansions of declare and undeclare.

In all, I would've written it

  (mac declare (name prop . body)
    `(after (do (= (metadata* ',name) ',prop)
                ,@body)
            (= (metadata* ',name) ,(metadata* name))))
But the last line shows we just wipe any declaration we made, so a global metadata table gets messy, unless we make the declarations themselves global (i.e., get rid of body).

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4 points by rocketnia 5252 days ago | link

It was just there for a brief pause between the macroexpansions of declare and undeclare.

If we want to change the behavior of other macros for a certain region of code, then that pattern might be useful. Since we seem to be talking about static type declarations, which I presume would be taken into account at macro-expansion time, I think the "between the macroexpansions" behavior is the whole point.

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1 point by fallintothis 5249 days ago | link

Thank you for the insight. It's probably the most lucid I've been all thread. It didn't seem deliberate to me, but it could have feasibly been written that way to control other macros' expansions. This also pushes computation to expansion time, which might clarify ylando's objections about "wasting run time". Except those still confuse me: macro expansion happens once, inside a function's body or outside of it.

  arc> (mac m (expr)
         (prn "macro m has expanded")
         expr)
  #(tagged mac #<procedure: m>)
  arc> (def f (x)
         (m (+ x 1)))
  macro m has expanded
  #<procedure: f>
  arc> (f 1)
  2
But the original point seems lost because declare's story keeps changing. So, ylando: why do we need "ignores"?

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1 point by ylando 5249 days ago | link

why do we need "ignores"?

Try building a macro that change global value, expand code (with macros) and then change the value back. I think that this macro must use another macro to change the value back; like the undeclare macro above. The second macro expands into unnecessary code; so if you put it inside a function this unnecessary code will waste run time. If we have "ignore" macro, we can write macros that do not produce unnecessary code.

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4 points by fallintothis 5248 days ago | link

I think that this macro must use another macro to change the value back; like the undeclare macro above.

Not necessarily.

  (mac declare (name prop . body)
    (let old (metadata* name)
      (= (metadata* name) prop)
      `(after (do ,@body)
         (= (metadata* ',name) ,old))))
But this introduces redundant assignments after each execution of body. Using a macro that expands into "unnecessary code" can be cheaper.

  (mac declare (name prop . body)
    (let old (metadata* name)
      (= (metadata* name) prop)
      `(after (do ,@body)
         (undeclare ,name ,old))))

  (mac undeclare (name old)
    (= (metadata* name) old)
    nil)
This introduces a redundant nil in the after block, and using after is a bit slower than just a do1. But we can't use do1 because this "do all the work at macro-expansion" approach is so touchy that it breaks:

  arc> (load "macdebug.arc") ; see http://arclanguage.org/item?id=11806
  nil
  arc> (macwalk '(declare name prop a b c))
  Expression --> (declare name prop a b c)
  macwalk> :s
  Macro Expansion ==>
    (do1 (do a b c)
         (undeclare name nil))
  macwalk> :s
  Macro Expansion ==>
    (let gs2418 (do a b c)
      (undeclare name nil)
      gs2418)
  macwalk> :s
  Macro Expansion ==>
    (with (gs2418 (do a b c))
      (undeclare name nil)
      gs2418)
  macwalk> :s
  Macro Expansion ==>
    ((fn (gs2418)
       (undeclare name nil)
       gs2418)
     (do a b c))
  macwalk> :s
  Subexpression -->
    (fn (gs2418)
      (undeclare name nil)
      gs2418)
  macwalk> :s
  Subexpression --> (undeclare name nil)
  macwalk> :s
  Value ==> nil
  Value ==> gs2418
  Value ==> (fn (gs2418) nil gs2418)
  Subexpression --> (do a b c)
  macwalk> :a
  Value ==> (do a b c)
  Value ==>
    ((fn (gs2418) nil gs2418) (do a b c))
  ((fn (gs2418) nil gs2418) (do a b c))
Note that we reach undeclare before the actual body is expanded!

We can hack it without after or do1 (or mutation, but I avoid that anyway).

  (mac declare (name prop . body)
    (let old (metadata* name)
      (= (metadata* name) prop)
      (w/uniq (g1 g2)
        `(with (,g1 (do ,@body)
                ,g2 (undeclare ,name ,old))
           ,g1))))

  (mac undeclare (name old)
    (= (metadata* name) old)
    nil)
This way, declare expands in the right order and we only undeclare once, since it'll expand into nil. The nil is "unnecessary", which seems to be why you want ignore, but it's a terribly pedantic point: ignore is already accomplished by dead code elimination (http://en.wikipedia.org/wiki/Dead_code_elimination). This isn't even a case of "sufficiently smart compilers" for vanilla Arc, since mzscheme already implements the standard optimizations: function inlining, dead code elimination, constant propagation/folding, etc. (see http://download.plt-scheme.org/doc/html/guide/performance.ht...) should all be able to clean up whatever ac.scm generates. E.g.,

  (mac foo ()
    `(prn ',metadata*!name))

  (declare name bar (foo))
compiles to

  ((lambda (gs581 gs582) gs581)
   ((let ((| gs581| (lambda () (ar-funcall1 _prn 'bar)))) | gs581|))
   'nil)
which should be easy to optimize.

Worrying seems premature anyway. ac.scm and arc.arc themselves do plenty worse, and the differences here are essentially rounding error.

  arc> (time10 (w/stdout (outstring)
                 (repeat 1000000
                   (with (x (do (prn 'bar))
                          y nil)
                     x))))
  time: 43048 msec.
  nil
  arc> (time10 (w/stdout (outstring)
                 (repeat 1000000
                   (prn 'bar))))
  time: 43170 msec.
  nil
Final idea: if expansion-time computation can't be avoided, you can expand the macros manually, if only for the sake of your readers. As a bonus, it does away with the dead code.

  (mac declare (name prop . body)
    (let old (metadata* name)
      (= (metadata* name) prop)
      (do1 `(do ,@(map macex-all body)) ; see http://arclanguage.org/item?id=11806
           (= (metadata* name) old))))
However, I think the fragile expansion-time computation is a bigger issue than dead code.

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1 point by ylando 5247 days ago | link

I try:

  (def macex-all (e)
    (zap macex e)
    (if acons.e
        (map1 macex-all e)
        e))

  (mac declare (name prop . body)
    (let old (metadata* name) 
       (= (metadata* name) prop)  
       (let exp-body (macex-all body)
            (= (metadata* name) old)
            (cons 'do exp-body))))
and it works. thanks.

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2 points by evanrmurphy 5252 days ago | link

How would using ampersand over dot make macro writing much easier? Is it just that you find the notation more intuitive, or is there something else?

Personally I prefer the dot because I think it looks less jarring and there's the connection with improper lists, as pg mentions in the tutorial (http://ycombinator.com/arc/tut.txt):

  (These conventions are not as random as they seem.  The parameter
  list mirrors the form of the arguments, and a list terminated by
  something other than nil is represented as e.g. (a b . c).)

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2 points by ylando 5252 days ago | link

Suppose that you want to write a macro that define a function:

  (mac def-func (func-name func-body)
    (w/uniq first-arg
      (w/uniq rest-arg
         `(def ,func-name (,first-arg . ,rest-arg)
             ,@func-body))))
And it will not work. There is a problem with using dot in quasiquote.

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3 points by shader 5252 days ago | link

So your real question is why dots don't work in quasiquote, and what should be done to fix them. That's a question that we can relate to a lot better than what we originally thought was "I don't like dots"

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2 points by evanrmurphy 5252 days ago | link

Would someone mind being more explicit about how it doesn't work? After dotting the outer definition's rest parameter as well so that the first line reads,

  (mac def-func (func-name . func-body)
it seems to be working for me:

  arc> (def-func 1+1 (+ 1 1))
  #<procedure: 1+1>
  arc> (1+1 nil)
  2
If you're interested, here's a version of your macro with a few things cleaned up (some changes only subjectively better):

  (mac def-func (name . body)
    (w/uniq (first rest)
      `(def ,name (,first . ,rest)
         ,@body)))

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1 point by ylando 5252 days ago | link

It don't work with jarc16, it don't work with arc3. What is your version of arc?

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1 point by evanrmurphy 5252 days ago | link

arc3.1. So did you get an error message on trying

  (def-func 1+1 (+ 1 1))
or what? Did you dot the func-body rest parameter as well?

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1 point by ylando 5252 days ago | link

It works on arc3.1.

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