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2 points by palsecam 5602 days ago | link | parent

The same thing in Arc:

   (let num->occ (table [for i 0 9 (= _.i 0)])
      (repeat 1000000  ; 1 million iterations
         (++ (num->occ (mod (rand 15) 10))))
      (each k (sort < (keys num->occ))
         (prn k "\t" (num->occ k))))
(~ same output than the Perl version)

Just for information:

   $ time perl < test-rand15.pl
   0m1.545s
   $ time mzscheme -m -f as.scm < test-rand15.arc
   0m17.374s
   $ time java -jar rainbow.jar < test-rand15.arc2 
   0m32.104s